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I like to list all the questions I involved but each question should listed only once. If I want to see a list where I contributed a comment, answer or question I have to go to all actions. There for I get a list where each entry represents a action and I want a list like this, but destinct this list by questions.

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    Do you want the list to show you which of these actions you have taken, or is a list of all the questions you have asked or answered or where you have commented on a post sufficient? How about edits -- should questions you have edited (or edited an answer to) be included? I'm not sure precisely what your requirements are, but I expect the Stack Exchange Data Explorer should enable you to query effectively for what you are looking for. – Eliah Kagan Jan 22 '17 at 17:48
  • @EliahKagan The second one, just want a list with all posts I'm involved (I'm not care about edit). – Hölderlin Jan 22 '17 at 20:57
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This is impossible through vanilla StackExchange, but I've gone ahead and created a quick-n-dirty SE Data Explorer query that will show you most of your actions on-site. It will display one entry for each of:

  • Questions Posted
  • Answers Posted
  • Comments to a Question
  • Comments to an Answer
  • Edits to a Question
  • Edits to an Answer

Simply click on that, enter your User ID, and hit Run Query. You can get your user ID by looking at your profile page's URL. It'll be the number embedded after users/:

https://meta.askubuntu.com/users/613613/h%C3%B6lderlin

Meaning, your user ID is 613613.


Now, something to quickly note about SE Data Explorer. It only updates once a week, specifically 3 AM UTC on Sunday. This means that the data returned by the query given above will not be up-to-date, but will still give you a good idea of what's going on.

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  • Thx you get it, although I used the wrong term if I said "unify" I mean "unique" (distinct). I'm not care about edits like here – Hölderlin Jan 24 '17 at 8:51
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    If you want a list of questions you've answered, commented, asked, or commented on an answer, try this query. – Kaz Wolfe Jan 24 '17 at 18:32

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