## The Cantor set with Regex

1 0 1
1 0 1 0 0 0 1 0 1
1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1 0 1

The endpoints of Cantor set iteration *n* are always multiples of 3^{-n} (exercise).

So we can represent that iteration using each of the midpoints 3^{-n}·(j+0.5).

('\d' ⎕R '\0 0 \0') '1 0 1'
1 0 1 0 0 0 1 0 1

('\d' ⎕R '\0 0 \0')⍣3⊢ '1'
1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1 0 1

The Power (`⍣`

) operator iterates its left operand like in mathematics.